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2010/6/14 12:56:23

设函数f(x)在闭区间[0,1]上可导,且f(0)×f(1)<0,证明在开区间(0,1)内至少有一点a,使得2f(a)+af'(a)=0



2010/6/14 16:28:09

构造函数;g(x)=f(x)/x^2


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